Question
A body moving at 20 m/s decelerates uniformly at 5m/s2 till its speed becomes 10 m/s. The distance covered within this period is
Answer
The answer to the distance covered within this period is 30 meters.
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Here is the explanation to the answer
Data: Available values from the question
The initial velocity, u = 20 m/s
Deceleration, a = opposite of acceleration = – 5 ms-2
Final velocity, v = 10 m/s
Unknown: The values from we need to find
Distance covered, s = ?
Formula: The formula that will help us find the distance covered
From the equations of motion, v2 = u2 + 2as
after making s subject of the formula, we will have
s = (v2 – u2) / 2a
We will apply the above equation to solve the problem
Solution
After inserting our data into the formula, we will have
s = (v2 – u2) / 2a = (102 – 202) / 2(-5)
Which will give us
s = (100 – 400) / -10
Thus
s = – 300 / -10 = 30 m
Therefore, the distance covered s is 30 meters.