## Question

Calculate the number of moles of an ideal gas of volume 12.0 meter cube at a pressure of 6 x 10^{3} Nm^{-2} and 27 degree celsius. [R = 8.0 Jmol^{-1}k^{-1}]

### Answer

**Outcome:** The answer to the above question is 30 moles

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**Here is the method i apply to solve the problem**

**Data:** Revealed values from the question

Volume of the gas, V = 12.0 m^{3}

Pressure, P = 6 x 10^{3} Nm^{-2}

Temperature of the gas, T = 27^{0}C = 27 + 273 = 300 K

The universal gas constant, R = 8.0 Jmol^{-1}k^{-1}

**Unknown:** Unrevealed values from the question

Number of moles, n = ?

**Formula:** The formula we need to apply to solve the problem

Ideal gas equation (**PV = nRT**)

And since we are looking for n, then the formula to calculate the number of moles of an ideal gas is

**n = PV / RT**

**Solution**

We will insert our data into the formula

n = PV / RT = (6 x 10^{3} x 12) / ( 8.0 x 300)

Which implies that

n = 72,000 / 2,400 = 30 moles

**Therefore, the number of moles of an ideal gas is 30 moles.**

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