## Question

A projectile is launched at an angle of 30 degrees with a horizontal and a speed of 30 m/s. How much time does it spend in the air?

### Answer

**Outcome:**

The time spent by a projectile in the air is 3.06 seconds which is our final answer.

**Here is how I arrived at my answer**

**Data: Revealed values from the question:**

The angle of projection, θ = 30^{0}

Horizontal velocity, u = 30 m/s

There is also gravitational force pulling the object downward, g = 9.8 ms^{-2}

**Unknown: Unrevealed values from the question**

time spent in the air, t = ?

**Formula to solve the problem**

t = (2usinθ) / g

##### Solution

We will insert our revealed values into the formula to start solving the problem

t = (2usinθ) / g = (2 x 30sin30^{0}) / 9.8

The above expression will give us

t = (60 x 0.5) / 9.8 = 30 / 9.8

Which implies that

t = 3.06 s

**Therefore, the time spent in the air is 3.06 seconds.**

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