The nuclear mass of 141ba is 140.883 amu. calculate the binding energy per nucleon for 141ba.
The final answer to the above question is 1.365392 x 10-12 Joules
The revealed pieces of information from the above question are:
Nuclear mass = 140.883 amu
Since the Barium atom can be written as 14156Ba
The number of protons = 56 amu
Number of neutron = 141 – 56 = 85 amu
Hence to find the mass of both protons and neutrons, we will multiply their numbers by 1.00783 and 1.00867 respectively.
Mass of protons = 1.00783 x 56 = 56.43848 amu
The mass of neutrons = 1.00867 x 85 = 85.73695 amu
Now, to find the mass of a nucleon, we will use the equation below
Mass of Nucleon = mass of proton + mass of the neutron
Mass of Nucleon = 56.43848 + 85.73695 = 142.17543 amu
We will now find the mass defect
Mass Defect = Mass of Nucleon – Nuclear mass = 142.17543 – 140.883 = 1.29243 amu
The binding energy (BE) in MeV will now become
BE = 1.29243 x 931 MeV = 1203.25233 MeV
Since the question wants us to calculate the binding energy per nucleon for 141Ba, we will now say:
The binding energy per nucleon for 141 Ba = BE / 141 = (1203.25233) / 141 = 8.5337 MeV
We can further convert the above answer into joules by using 1 MeV = 1.6 x 10-13 J
This implies that
The binding energy per nucleon for 141 Ba = 8.5337 MeV = 8.5337 x 1.6 x 10-13 J = 1.365392 x 10-12 J
Therefore, the binding energy per nucleon of 141 Ba is 1.365392 x 10-12 Joules.
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