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On a 20-mile bike ride you ride the first 10 miles at an average speed of 8 mi/h.

Question
On a 20-mile bike ride, you ride the first 10 miles at an average speed of 8 mi/h.

(a) What must your average speed over the next 10 miles be in order to have a total average speed of 4 mi/h?

(b) What must your average speed over the next 10 miles be in order to have a total average speed of 12 mi/h?

(c) Given your answer in part (b), is it possible to attain a total average speed of 16 mi/h for the entire 20-mile ride? Explain.

Solution

Let us solve Problem 2.54 step by step.

Given data:

• The total bike ride distance = 20 miles

• First 10 miles average speed = 8 mi/h

• We need to find the required average speed for the second 10 miles to achieve certain total average speeds.

Step 1: Definition of Average Speed

The average speed over the entire trip is given by:

Average speed = total distance/ total time


where Total time is:

Ttotal = t1 + t2

with:

• t1 = time taken for first 10 miles

• t2 = time taken for second 10 miles

The time for a given distance  at speed  is: t = d/v

Step 2: Time for First 10 Miles

t1 = 10/8 = 1.25 hours

Step 3: Find Required Speed for Given Average Speeds

(a) Required speed for total average speed of 4 mi/h

20/(t1 + t2) = 4

Substituting t1 = 1.25 hours

t2 = 5 – 1.25 = 3.75 hours

v2 = 10/t2 = 10/3.75 =2.667 mi/h

So, the required speed is 2.67 mi/h.

(b) Required speed for total average speed of 12 mi/h

20/(t1 + t2) = 12

ttotal = 20/12 = 1.667 hours

t2 = 1.67 – 1.25 = 0.42 hours

v2 = 10/0.42 = 23.81 mi/h

So, the required speed is 23.8 mi/h.

(c) Is it possible to attain an average speed of 16 mi/h for the total 20 miles?

20/(t1 + t2) = 16

Ttotal = 20/16 = 1.25 hours

t2 = 1.25 – 1.25 = 0

Since time cannot be zero, it is impossible to achieve an average speed of 16 mi/h for the total trip.

Final Answers

(a) Required speed = 2.67 mi/h

(b) Required speed = 23.8 mi/h

(c) Not possible to achieve 16 mi/h average speed.