## Question

After an airplane takes off, it travels 10.4 km west, 8.7 km north, and 2.1 km up. How far is it from the take-off point?

### Answer

**The final answer to this question is 13.7 kilometers (km)**

#### Explanation

We will follow the following steps to solve the problem

**Data: Revealed information from the question**

If we allow negative x to represent the western direction = 10.4 km .

Then the eastern direction will be, x = – 10.4 km

Along the northern direction, we have y = 8.7 km

We also have z = 2.1 km

**Unknown: Unrevealed information**

Distance from the takeoff point, S = ?

**Formula: The equation that will help us solve the problem**

S = √ (x^{2} + y^{2} + z^{2})

#### Solution

We will now apply our data into the formula to solve the problem

S = √ (x^{2} + y^{2} + z^{2}) = √ ((-10.4)^{2} + 8.7^{2} + 2.1^{2})

Which implies that

S = √(108.6 + 75.69 + 4.41) = √188.7

Therefore, the distance from the takeoff point is

S = 13.7 km

**Hence, the distance s from the takeoff point is 13.7 kilometers.**

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