0:02
C IND and the cap are 5 and micro
0:09
respectiv calulate the resonance
0:11
frequency of the C to calculate
0:14
resonance frequency of the CLE first
0:17
look at the question again say
0:26
are and two micro respectively so we
0:50
micro which is the therefore we have our
0:54
Capac C isal to 2 micro
1:09
* because micro is 10us
1:15
6 calculate the resonance
1:20
frequency of the S we have to calculate
1:31
so now we have all this next we need to
1:35
do is for formula the formula that will
1:39
suit this problem is f =
1:48
2un of L C this is the formula forant
1:55
frequency and see Series S
2:37
6 5 * 2 * 10^ - 6 which is f now I try
2:47
to break it down we will have uh when we
2:51
use our calor you see that this will now
3:25
will = to one this one
3:44
1 is going to give us
3:54
3.16 to the power of - 3 so when you
4:00
calculate this you have f is =
4:22
987 * 10 power of - 2 and this is what
4:30
therefore finally you have not one over
4:32
this is going to give you
4:42
hats unit of frequency ons and this is
4:46
our fin answer so as you can see this is
4:51
what we're able to get and