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Calculate the peak voltage of a mains supply of r.m.s value 220v. [NECO 2000]
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0:01
calculate the P voltage of a mean supply
0:04
of root me Square value 220 volts this
0:09
question is from me
0:11
2000 we are to calculate the the voltage
0:15
the first thing we need to do is to look
0:17
at the question and extract our data
0:20
from this question it says calculate the
0:23
peak voltage which means we have to
0:26
calculate B
0:32
B
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not we have calculate three
0:42
not question ma
0:48
here of a M Supply of root me Square
0:54
value 220
0:57
volt root me squ value
1:00
b
1:02
r
1:03
Ms is equal to
1:06
[Music]
1:07
220
1:09
volts therefore this is our data from
1:12
this
1:14
question now we need to know which
1:17
formula is suitable for
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this
1:23
question we know that we have B is equal
1:29
to
1:30
[Music]
1:33
1.41
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4 B root me S as a formula to find the
1:42
big
1:44
voltage
1:45
now in this case now we'll now solve the
1:49
problem by
1:51
saying since B not is not known to
1:55
us we will now say b not is equals to
2:02
[Music]
2:04
1.414
2:07
1.41
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4 * bot me
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S and from our data bot square is equal
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to 220 volts therefore we have
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220 now
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next thing we need to do is to say b not
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is equals
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to if you use calculator you'll see that
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141
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1.414 * 220 is going to give
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us
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3
2:49
11
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approximately and the unit of fig
2:54
voltage is in BTS therefore 311 volts
2:59
and this this is our final answer
3:01
therefore as you can see
3:05
here when we extracted our data we had B
3:10
not unnown which is unknown as bot
3:14
square is 220
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BTS we then move to the formula which is
3:21
B and B is the F voltage which is
3:26
1.414 bot s
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now to solve the problem we will say B =
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1.414 * bot s so in this case now we
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substitute the value of we change
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instead of Bot s we now write
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220 which is 1.414 *
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220 and now we'll get B not =
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311 volt which is our final answer
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