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A voltage supply of 12Vrms and frequency 90Hz is connected to a 4Ω resistor. Calculate the peak
Dec 9, 2024
A voltage supply of 12Vrms and frequency 90Hz is connected to a 4Ω resistor. Calculate the peak value of the current.
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0:02
a voltage supply of 12 bot s and
0:06
frequency
0:08
90z is connected to a 4 Ohms
0:12
resistor calculate the F value of the
0:16
current now a voltage
0:20
supply of 12 s which means we
0:26
have
0:28
B root means
0:30
Square =
0:32
to
0:34
12
0:37
sorry
0:38
12
0:42
volts and
0:44
frequency of 90
0:46
HZ is connected to a 4 Ohms resistor in
0:51
this case we also have a
0:56
resistance which is equals to 4
1:02
ohms calculate the
1:05
peak value of the current calculate the
1:09
pi value of the current which is I not
1:14
what is I
1:15
not remember that the formula for I
1:20
not I not is equal
1:23
to
1:25
IUN
1:27
s time
1:30
<
1:31
tk2 this is I not = IUN * < tk2 which is
1:37
the formula for I but we don't have iot
1:42
me S and we need to find it remember
1:46
again that resistance is equal to
1:51
voltage over
1:53
current therefore this is the same as to
1:56
say bot s all
2:00
over
2:03
IUN me
2:06
squ and to find I root means squ because
2:10
we have voltage we also have
2:15
resistance therefore in this case we
2:17
will now say
2:23
that we'll now say that since we have
2:26
our
2:28
voltage we have our
2:30
resistance and R isal to
2:34
bot s all
2:38
IUN
2:40
s by cross
2:42
multiplication we'll end up
2:45
having
2:48
IUN s *
2:52
resistance which is equal to B root
2:56
me
2:58
squ however looking for I squ therefore
3:01
we can divide both sides by
3:04
by this will cancel this leaving us with
3:09
IUN
3:12
s isal to
3:17
b² all
3:19
over
3:22
R therefore we now go back to our data
3:26
which says that b s = 12 therefore this
3:29
case we will now come here and say b s
3:33
isal 12 from here therefore we change it
3:37
with
3:37
12 right 12
3:40
here all over R from here our R is 4 OHS
3:46
remember from the question it say 4 Ohms
3:49
therefore we now
3:52
Sayid
3:53
4 and this is going to give us 12 / 4 so
3:59
let me write it
4:01
here
4:03
IUN s = 12 4 will give us three and this
4:12
is therefore iot S = 3 now that we have
4:17
iot S we go back to the main equation
4:20
that we supposed to use to find the P
4:23
value of the current which is I not
4:27
therefore in this case
4:31
we will now say
4:33
that I
4:36
not I is equal to
4:41
IUN
4:43
m² * <
4:46
tk2 which is equal to iot me S is = 3
4:52
* tk2 and this is going to give us 3 <
4:58
tk2 to change it from short form let me
5:02
type my own calculator to see what I'm
5:04
going to
5:05
get if I
5:08
first this is going to give me
5:13
uh this is going to give
5:15
me I
5:18
not = to
5:24
4.2 a which is the P value of the
5:27
current and this is our final answer
5:33
so you can see it
#Power Supplies
#Engineering & Technology
#Physics
#Physics