The current through a resistor in an a.c circuit is given as 2sinwt. Determine the d.c equivalent
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Jan 23, 2025
The current through a resistor in an a.c circuit is given as 2sinwt. Determine the d.c equivalent of the current
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0:01
the current through a resistor in an AC
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circuit is given as 2 sin Omega T
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determine the DC equivalent of the
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current in this case what we need to do
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is to First Look at the question and
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then if possible try and extract our
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data the
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current through a resistor in an AC
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circuit is giv us
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2 sin Omega
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T the
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current
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I is equal
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to
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2 sin Omega
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T determine the DC equivalent of the
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current in this case the DC equivalent
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of the AC is the root me S
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current that is I root me Square
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therefore the DC equivalent is the I
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root me iot mean squ we have to find iot
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mean
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squ now for us to continue we must
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identify the formula that we supposed to
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use therefore we will now say from the
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equation I is equal to
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I sin
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Omega
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T if you look at I not which is the PE
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current here is
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two therefore the current PE current
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here I is equal
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to to
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and we
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have I we have I not which is the V
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current Now we move to the next
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step which
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is IUN me S this is the formula that is
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supposed to lead us to to our answer
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which is equals
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to iot S is equal to
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I over <
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tk2
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I
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overun of 2 and this is the formula we
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going to use
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therefore
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now since we have I
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I2 we now
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say
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IUN me S will now solve the problem as
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is equal instead of I I here isal
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2
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[Music]
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2 square root of
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two we now turn it remember our
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our topic from mathematics which is
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Sol we now say iot means
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squ isal
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to 2
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overun of 2
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* < TK of 2 over < TK of 2 why
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because x / x = 1
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therefore < TK of
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2/ < TK 2 =
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1 hence we will now
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say this isal to 2k2 is = 2 < TK 2 all
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over < TK 2 * < TK 2 is = < TK of two by
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2 and this is going to give us this is
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going to be 2 Square
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t of of 2 all overun
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of 2x 2 is =
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4
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and iot me
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S is equal
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to 2 < tk2 2 < TK of 2 all over squ root
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of
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4 square root of
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4 and this is going to give
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us 2 < TK of 2 all over < TK 4 is =
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2 and two will cancel two leing know
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with IUN me
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S is equal to square root of 2
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which is our final answer and
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the unit is in unfair for < TK of 2 and
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and this is what we
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have from this
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question you can see
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that I read it again
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