Question
A possible fusion reaction is 12H + 12H —-> 13H + 11H + Q, where Q is the energy released as a result of the reaction. If Q = 4.03 eV, Calculate the atomic mass of 13H in atomic mass units. [12H = 2.0141u, 11H = 1.00783u, 1u = 931MeV]
Answer
12H + 12H —-> 13H + 11H + Q
Let X = atomic of 13H in u,
1u = 931MeV
Therefore, 4.03MeV = (4.03u/931) = 0.004329u
Substitute given values into the nuclear equation to obtain:
2.01410 + 2.01410 —-> x + 1.00783 + 0.004329
Hence, 4.0282 = x + 1.01216
Therefore, x = 4.0282 – 1.01216 = 3.01604u
